# Question #f9956

##### 1 Answer

Here's how you can do that.

#### Explanation:

A solution's concentration in **parts per million**, or **ppm**, tells you the number of grams of solute you get for every

grams of solution.

Similarly, a solution's concentration in **parts per billion**, or **ppb**, tells you the number of grams of solute present for every

#10^9 = 1,000,000,000#

grams of solution.

In your case, a solution that has a concentration of **for every** **for every**

So in order to convert the

#"DF" = (10^9 color(red)(cancel(color(black)("g"))))/(10^6color(red)(cancel(color(black)("g")))) = color(blue)(1000) -># thedilution factor

So, for example, if you start with

#color(blue)(1000) * "100 g" = 10^5color(white)(.)"g"#

So, to sum this up, you can convert a **times higher** than the mass of the initial sample.