# Question #13d73

Sep 15, 2017

You use 0.06 mL of liquid A, 0.18 mL of liquid B, 0.15 g of solid C, 0.114 g of solid D, 0.11 g of solid E, and enough water to make a total of 100 g.

#### Explanation:

I assume you will measure the liquids by volume and the solids my mass.

The solution will have about the same density as water, so you are making 100 g of solution.

Volume of liquid A

$\text{Volume" = 100 color(red)(cancel(color(black)("g soln"))) × (0.05 color(red)(cancel(color(black)("g A"))))/(100 color(red)(cancel(color(black)("g soln")))) × "1 mL A"/(0.902 color(red)(cancel(color(black)("mL A")))) = "0.06 mL A}$

Volume of liquid B

$\text{Volume" = 100 color(red)(cancel(color(black)("g soln"))) × (0.16 color(red)(cancel(color(black)("g B"))))/(100 color(red)(cancel(color(black)("g soln")))) × "1 mL B"/(0.876 color(red)(cancel(color(black)("mL A")))) = "0.18 mL B}$

Mass of solid C

$\text{Mass" = 100 color(red)(cancel(color(black)("g soln"))) × (0.15 color(red)(cancel(color(black)("g C"))))/(100 color(red)(cancel(color(black)("g soln")))) = "0.15 g C}$

Mass of solid D

$\text{Mass" = 100 color(red)(cancel(color(black)("g soln"))) × (0.114 color(red)(cancel(color(black)("g D"))))/(100 color(red)(cancel(color(black)("g soln")))) = "0.114 g D}$

Mass of solid E

$\text{Mass" = 100 color(red)(cancel(color(black)("g soln"))) × (0.11 color(red)(cancel(color(black)("g E"))))/(100 color(red)(cancel(color(black)("g soln")))) = "0.11 g E}$

So, to prepare the solution, you will use 0.06 mL A, 0.18 mL B, 0.15 g C, 0.114 g D, 0.11 g E, and enough water to make a total of 100 g.