I assume you will measure the liquids by volume and the solids my mass.
The solution will have about the same density as water, so you are making 100 g of solution.
Volume of liquid A
#"Volume" = 100 color(red)(cancel(color(black)("g soln"))) × (0.05 color(red)(cancel(color(black)("g A"))))/(100 color(red)(cancel(color(black)("g soln")))) × "1 mL A"/(0.902 color(red)(cancel(color(black)("mL A")))) = "0.06 mL A"#
Volume of liquid B
#"Volume" = 100 color(red)(cancel(color(black)("g soln"))) × (0.16 color(red)(cancel(color(black)("g B"))))/(100 color(red)(cancel(color(black)("g soln")))) × "1 mL B"/(0.876 color(red)(cancel(color(black)("mL A")))) = "0.18 mL B"#
Mass of solid C
#"Mass" = 100 color(red)(cancel(color(black)("g soln"))) × (0.15 color(red)(cancel(color(black)("g C"))))/(100 color(red)(cancel(color(black)("g soln")))) = "0.15 g C"#
Mass of solid D
#"Mass" = 100 color(red)(cancel(color(black)("g soln"))) × (0.114 color(red)(cancel(color(black)("g D"))))/(100 color(red)(cancel(color(black)("g soln")))) = "0.114 g D"#
Mass of solid E
#"Mass" = 100 color(red)(cancel(color(black)("g soln"))) × (0.11 color(red)(cancel(color(black)("g E"))))/(100 color(red)(cancel(color(black)("g soln")))) = "0.11 g E"#
So, to prepare the solution, you will use 0.06 mL A, 0.18 mL B, 0.15 g C, 0.114 g D, 0.11 g E, and enough water to make a total of 100 g.
