# If the mass of a single electron is 9.10938xx10^-31*kg, how many electrons constitute a mass of 1*g?

Sep 16, 2017

You could have quoted the $\text{electronic mass}$, ..........

#### Explanation:

And the mass of electron is ..................$9.10938 \times {10}^{-} 31 \cdot k g \equiv 9.10938 \times {10}^{-} 28 \cdot g$

And thus number of electrons is.....

$\frac{1.000 \cdot g}{9.10938 \times {10}^{-} 28 \cdot g} = 1.098 \times {10}^{27}$ $\text{individual electrons.}$

And note that the charge of this quantity of electrons, i.e. −1.602×10^(-19) C*"electron"^-1xx1.098xx10^27*"electron" would be phenomenonally GREAT.