Question

If the mass of a single electron is `9.10938xx10^-31*kg`, how many electrons constitute a mass of `1*g`?

Answer 1

You could have quoted the `"electronic mass"`, ..........

Explanation:

And the mass of electron is ..................`9.10938xx10^-31*kg-=9.10938xx10^-28*g`

And thus number of electrons is.....

`(1.000*g)/(9.10938xx10^-28*g)=1.098xx10^27` `"individual electrons."`

And note that the charge of this quantity of electrons, i.e. `−1.602×10^(-19) C*"electron"^-1xx1.098xx10^27*"electron"` would be phenomenonally GREAT.