If the mass of a single electron is #9.10938xx10^-31*kg#, how many electrons constitute a mass of #1*g#?

1 Answer
Sep 16, 2017

Answer:

You could have quoted the #"electronic mass"#, ..........

Explanation:

And the mass of electron is ..................#9.10938xx10^-31*kg-=9.10938xx10^-28*g#

And thus number of electrons is.....

#(1.000*g)/(9.10938xx10^-28*g)=1.098xx10^27# #"individual electrons."#

And note that the charge of this quantity of electrons, i.e. #−1.602×10^(-19) C*"electron"^-1xx1.098xx10^27*"electron"# would be phenomenonally GREAT.