How do we draw the graph of #r^2=-9cos2theta#?

1 Answer
Feb 15, 2018

Please see below.

Explanation:

Observe that as #r^2=-9cos2theta#, we do not have a real value of #r# when #theta# is in the interval #(-pi/4,pi/4)# and #((3pi)/4,(5pi)/4)# as in these intervals #cos2theta# is positive and accordingly #r^2<0#.

Hence, in the domain of #theta# is #[pi/4,(3pi)/4]uu[(5pi)/4,(7pi)/4]#, let us consider known values of #theta# on unit circle

#{pi/4,pi/3,pi/2,(2pi)/3,(3pi)/4,(5pi)/4,(4pi)/3,(3pi)/2,(5pi)/3,(7pi)/4}#

and corresponding values of #r^2# are

#{0,9/2,9,9/2,0,0,9/2,9,9/2,0}#

and values of #r# are #{0,3/sqrt2,3,3/sqrt2,0,0,3/sqrt2,3,3/sqrt2,0}#

and graph appears as

enter image source here