What is the domain of #f(x)=sqrt(x-7)# and #h(x)=(3x)/(x^2-4)#?

1 Answer
Feb 15, 2018

Please see below.

Explanation:

#f(x)=sqrt(x-7)# is not defined for #x<7# and

hence domain is #x inRR:x>=7#

In interval notation it is #[7,oo)#.

#h(x)=(3x)/(x^2-4)# is not defined for #x^2=4#

i.e. for #x=2# and #x=-2#

and domain is #x inRR:x^2!=4#

In interval notation it is #(-oo,-2)uu(-2,2)uu(2,oo)#