Question #a9ccf

1 Answer
Feb 3, 2018

The solution are #((x_1),(x_2))=((7/4),(0))+((1/4),(1))*s# and #((x_1),(x_2),(x_3),(x_4))=((-5),(3),(2),(0))+((-1),(1),(-1),(1))*s#

Explanation:

Rewriting the equations as

#((-4,1),(12,-3))((x_1),(x_2))=((-7),(12))#

#(R2larrR2+3R1)#

#((-4,1),(12,-3))~((-4,1),(0,0))#

Therefore,

the equation is

#-4x_1+x_2=-7#

#x_1=x_2/4+7/4#

The solutions are

#x_1=7/4+1/4x_2#

#x_2=x_2#

#((x_1),(x_2))=((7/4),(0))+((1/4),(1))*s#

The equations are

#x_1=-2-x_2#

#x_2=5-x_3=5-(2-x_4)=3+x_4#

#x_3=2-x_4#

#x_1=-5-x_4#

#((x_1),(x_2),(x_3),(x_4))=((-5),(3),(2),(0))+((-1),(1),(-1),(1))*s#