Question #ced37

1 Answer
Narad T.
Nov 2, 2017

The answer is #((x),(y),(z))=((3/4),(0),(0))+((5/4),(1),(0))s+((-7/4),(0),(1))t#

Explanation:

The equation of the plane is

#-4x+5y-7z=-3#

Therefore,

#4x=3+5y-7z#

#x=3/4+5/4y-7/4z#

Let #y=s# and #z=t#

Then,

#(x,y,z)=(3/4+5/4s-7/4t,s,t)#

So,

#((x),(y),(z))=((3/4),(0),(0))+((5/4),(1),(0))s+((-7/4),(0),(1))t#

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