Question #2ae51

1 Answer
Dec 23, 2017

Please see below.

Explanation:

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Please edit your question and make sure it is posted accurately. It is not clear what the problem is asking. Since log of anything to the same base is equal to #1#, i.e. #log_aa=1#, and natural log #(ln)# has a base of #e#, #lne=1#.

The way you have written your equation, it becomes:

#3-2xlne=ln4#

#3-2x(1)=ln4#

#3-2x=ln4#

#2x=3-ln4#

#x=(3-ln4)/2#

Is this what you meant?