Question #5952a

1 Answer
Sep 22, 2017

int(x^3/sqrt9+x^2 )dx=x^4/12+x^3/3+C

Explanation:

int(x^3/sqrt9+x^2 )dx
simpified
int(x^3/3+x^2 )dx

using general formula intx^ndx=x^(n+1)/(n+1)+C

int(x^3/3+x^2 )dx=intx^3/3dx+intx^2dx
=(1/3)x^4/4+x^3/3+C
=x^4/12+x^3/3+C