# Question #3c4fa

Sep 25, 2017

the squirrel was displaced by 2.69 m at an angle of ${68}^{o}$ from the horizontal plane with respect to their original position.

#### Explanation:

vertical displacement: 2.50m
horizontal displacement: 1.00m
$\sqrt{2.50 {m}^{2} + 1.00 {m}^{2}} = {c}^{2}$
$c = 2.69 m$

the angle at which the displacement occurs is:
$\sin O = \frac{o p p}{h y p}$
${\sin}^{-} 1 \left(\frac{o p p}{h y p}\right) = {\sin}^{-} 1 \left(\frac{2.5}{2.69}\right) = O$
$O = {68}^{o}$