How do you write and graph the equation of a circle with center at (5, 4) and a radius of #4/7#?
2 Answers
See a solution process below:
Explanation:
The equation for a circle is:
Where
Substituting the values from the problem gives:
graph{(x-5)^2+(y-4)^2-16/49=0 [-1, 13, -1, 6]}
Explanation:
#"the standard form of the equation of a circle is"#
#color(red)(bar(ul(|color(white)(2/2)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(2/2)|)))#
#"where "(a,b)" are the coordinates of the centre and r is"#
#"the radius"#
#"here "(a,b)=(5,4)" and "r=4/7#
#(x-5)^2+(y-4)^2=16/49larrcolor(red)"is the equation of the circle"#
graph{(x-5)^2+(y-4)^2-16/49=0 [-10, 10, -5, 5]}