Given a mass of #306.0g# of mercury, the which has a volume of #22.5mL#, what is the density of mercury in #g*mL^-1#?

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Answer 1 · 2017-10-01T01:30:03

#rho_"density"="Mass"/"volume"#, and thus we get units of #g*mL^-1#....

And so #rho_"mercury"=(306.0*g)/(22.5*mL)=13.6*g*mL^-1#....

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Given a mass of #306.0*g# of mercury, the which has a volume of #22.5*mL#, what is the density of mercury in #g*mL^-1#?