How do you simplify #35/56#?

2 Answers
Sep 28, 2017

We can factor the numerator and denominator as:

#35/56 => (7 xx 5)/(7 xx 8) => (color(red)(cancel(color(black)(7))) xx 5)/(color(red)(cancel(color(black)(7))) xx 8) => 5/8#

Oct 1, 2017

#(35div7)/(56div7) = 5/8#

Explanation:

To write a fraction in its simplest form, you divide the numerator and denominator by the highest common factor.

#35 and 56# are both multiples of #7" "HCF=7#

#(35div7)/(56div7) = 5/8#

Dividing by #7/7# is the same as dividing by #1#. This does not change the value, only what a number looks like.

We often call this process 'cancelling'

#cancel35^5/cancel56^8 = 5/8#

Compare the decimals:

#35/56 = 0.625 and 5/8= 0.625#