# Question #913e1

##### 1 Answer

#### Explanation:

An interesting approach to have here would be to convert the density of mercury from *grams per milliliter* to *kilograms per milliliter* by using the fact that

#color(blue)(ul(color(black)("1 kg" = 10^3color(white)(.)"g")))#

So, you know that mercury has a density of **every**

Use the aforementioned conversion factor to find the density of mercury in kilograms per milliliter

#"13.546 g mL"^(-1) = (13.546 color(red)(cancel(color(black)("g"))))/"1 mL" * "1 kg"/(10^3color(red)(cancel(color(black)("g")))) = "0.013546 kg mL"^(-1)#

So if

#37.0 color(red)(cancel(color(black)("mL"))) * "0.013546 kg"/(1color(red)(cancel(color(black)("mL")))) = color(darkgreen)(ul(color(black)("0.501 kg")))#

The answer is rounded to three **sig figs**, the number of sig figs you have for the volume of the sample.