# Question #913e1

Sep 28, 2017

$\text{0.501 kg}$

#### Explanation:

An interesting approach to have here would be to convert the density of mercury from grams per milliliter to kilograms per milliliter by using the fact that

$\textcolor{b l u e}{\underline{\textcolor{b l a c k}{\text{1 kg" = 10^3color(white)(.)"g}}}}$

So, you know that mercury has a density of ${\text{13.546 g mL}}^{- 1}$, which means that every $\text{1 mL}$ of mercury has a mass of $\text{13.546 g}$.

Use the aforementioned conversion factor to find the density of mercury in kilograms per milliliter

${\text{13.546 g mL"^(-1) = (13.546 color(red)(cancel(color(black)("g"))))/"1 mL" * "1 kg"/(10^3color(red)(cancel(color(black)("g")))) = "0.013546 kg mL}}^{- 1}$

So if $\text{1 mL}$ of mercury has a mass of $\text{0.013546 kg}$, you can say that $\text{37.0 mL}$ of mercury will have a mass of

$37.0 \textcolor{red}{\cancel{\textcolor{b l a c k}{\text{mL"))) * "0.013546 kg"/(1color(red)(cancel(color(black)("mL")))) = color(darkgreen)(ul(color(black)("0.501 kg}}}}$

The answer is rounded to three sig figs, the number of sig figs you have for the volume of the sample.