Question

Question #913e1

Answer 1

`"0.501 kg"`

Explanation:

An interesting approach to have here would be to convert the density of mercury from grams per milliliter to kilograms per milliliter by using the fact that

`color(blue)(ul(color(black)("1 kg" = 10^3color(white)(.)"g")))`

So, you know that mercury has a density of `"13.546 g mL"^(-1)`, which means that every `"1 mL"` of mercury has a mass of `"13.546 g"`.

Use the aforementioned conversion factor to find the density of mercury in kilograms per milliliter

`"13.546 g mL"^(-1) = (13.546 color(red)(cancel(color(black)("g"))))/"1 mL" * "1 kg"/(10^3color(red)(cancel(color(black)("g")))) = "0.013546 kg mL"^(-1)`

So if `"1 mL"` of mercury has a mass of `"0.013546 kg"`, you can say that `"37.0 mL"` of mercury will have a mass of

`37.0 color(red)(cancel(color(black)("mL"))) * "0.013546 kg"/(1color(red)(cancel(color(black)("mL")))) = color(darkgreen)(ul(color(black)("0.501 kg")))`

The answer is rounded to three sig figs, the number of sig figs you have for the volume of the sample.