Find the value of #(sectheta+tantheta)(sectheta-tantheta)#?

1 Answer
Shwetank Mauria
Dec 14, 2017

#(sectheta+tantheta)(sectheta-tantheta)=sec^2theta-tan^2theta=1#

Explanation:

#(sectheta+tantheta)(sectheta-tantheta)#

= #sectheta(sectheta-tantheta)+tantheta(sectheta-tantheta)#

= #sec^2theta-secthetatantheta+tanthetasectheta-tan^2theta#

= #sec^2theta-cancel(secthetatantheta)+cancel(tanthetasectheta)-tan^2theta#

= #sec^2theta-tan^2theta#

= #1#

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