Question #89af9

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Answer 1 · 2018-02-20T09:38:04

![my scanner]
see explanation.

my scanner

Answer 2 · 2018-02-20T09:53:40

Kindly refer to the Explanation.

Prerequisite : Dividendo D :

#"(D) : "a/b=c/d hArr (a-b)/b=(c-d)/d#.

We know that, #1-sin^2t=cos^2t#.

#:. (1+sint)(1-sint)=(cost)(cost)#.

#rArr (1+sint)/cost=cost/(1-sint)#.

#:. (1+sint-cost)/cost={cost-(1-sint)}/(1-sint), i.e., #

# (1+sint-cost)/cost=(cost-1+sint)/(1-sint), or, #

# (1+sint-cost)/(cost-1+sint)=cost/(1-sint)=(1+sint)/cost#.