# Question #a1a19

Depending on what your teacher is looking for, you might be overthinking this one.

#### Explanation:

Immediate after heating the copper sulfate forms a dry, light blue solid.

Right after the heating is complete the reaction is:

$C u S {O}_{4} \cdot 5 {H}_{2} O \left(s\right) \to C u S {O}_{4} \left(s\right) + 5 {H}_{2} O \left(g\right)$

The addition of water reverses the removal of water.

$C u S {O}_{4} \left(s\right) + 5 {H}_{2} O \left(l\right) \to C u S {O}_{4} \cdot 5 {H}_{2} O \left(s\right)$

If you add exactly 5 parts water for every one part copper sulfate the solid will return to being $C u S {O}_{4} \cdot 5 {H}_{2} O \left(s\right)$.

Adding any extra water will cause the formation of a copper sulfate solution of$C u S {O}_{4} \cdot 5 {H}_{2} O \left(a q\right)$.

Hope this helps!