Question

Question #eed15

Answer 1

The statement is true.

Explanation:

We know this trig identity:

`cos^2x+sin^2x=1`

If we divide everything by `sin^2x`, we get a new identity:

`cos^2x/sin^2x+sin^2x/sin^2x=1/sin^2x`

`cot^2x+1=csc^2x`

We can now use this new identity to simplify our expression to show that it is true:

`(cos^2x)/(sin^2x)+1=csc^(2)x`

`cot^2+1=csc^2x`

`csc^2x=csc^2x`