If #rho_"benzene"=0.8786*g*mL^-1#, what is the mass of a #250*mL# volume of benzene?

2 Answers
Oct 4, 2017

Assuming density is in #"kg"/m^3#

#rho=m/v#
#=>rho*v=m#

#250 mL=0.25L=0.00025m^3#
#0.8786"kg"/cancel (m^3)*0.00025cancel(m^3#

#=0.00021965 "kg OR "219.65"mg"#


PS :-
The actual density of benzene is #876"kg"/m^3#, which means the mass would be #0.219 "kg OR "219"g"#

Oct 4, 2017

#"Mass of benzene"~=220*g#.....

Explanation:

By definition, #rho_"density"="Mass of stuff"/"Volume of stuff"#

And clearly to get the mass of stuff we take the product.....

#rho_"density"xx"volume of stuff"="Mass of stuff"#

#=0.8786*g*mL^-1xx250*cancel(mL)=??*g#

A mass as required.......