Question #b9be5

1 Answer
Feb 28, 2018

See a solution process below:

Explanation:

The formula for the volume of a cone is:

#V_c = pir^2h/3#

To find the radius we divide the diameter by #2# giving:

#(4"in")/2 = 2"in"#

Substituting #2"in"# for #r# and #6"in"# for #h# and calculating #V_c# gives:

#V_c = pi xx (2"in")^2 xx (6"in")/3#

#V_c = pi xx 4"in"^2 xx 2"in"#

#V_c = pi xx 8"in"^3#

Using #3.14# to approximate #pi# gives:

#V_c = 3.14 xx 8"in"^3#

#V_c = 25.12"in"^3#

The formula for the volume of a cylinder is:

#V_y = pir^2h#

Substituting #2"in"# for #r# and #6"in"# for #h# and calculating #V_y# gives:

#V_y = pi xx (2"in")^2 xx 6"in"#

#V_y = pi xx 4"in"^2 xx 6"in"#

#V_y = pi xx 24"in"^3#

Using #3.14# to approximate #pi# gives:

#V_y = 3.14 xx 24"in"^3#

#V_y = 75.36"in"^3#

The difference in the volume of the two shapes is:

#V_y - V_c#

#75.36"in"^3 - 25.12"in"^3 = 50.24"in"^3#

Another process to solve this would be to first subtract the formulas:

#V_y - V_c#

#pir^2h - pir^2h/3#

#pir^2(1h - h/3)#

#pir^2h(1 - 1/3)#

#pir^2h2/3#

Now substituting and calculating gives:

#3.14 xx (2"in")^2 xx 6"in" xx 2/3#

#3.14 xx 4"in"^2 xx 6"in" xx 2/3#

#3.14 xx 24"in"^3 xx 2/3#

#3.14 xx (48"in"^3)/3#

#3.14 xx 16"in"^3#

#50.24"in"^3#