Question

What mass of calcium carbonate will react completely with `4.1*g` `HCl`?

Answer 1

What mass of calcium carbonate will react completely with `4.1*g` `HCl`?

Explanation:

We need (i) a stoichiometric equation....

`CaCO_3(s)+2HCl(aq) rarr CaCl_2(s) + CO_2(g) + H_2O(l)`

And (ii) we need equivalent quantities of hydrogen chloride.

`"Moles of HCl"=(4.1*g)/(36.46*g*mol^-1)=0.113*mol`.

And this will react with half an equiv of `CaCO_3(s)`

`0.113*molxx1/2xx100.09*g*mol^-1=5.63*g`.....