# Question #7aed4

Oct 9, 2017

$x = 6.9162280580253 , \setminus q \quad x = - 8.9162280580253$

#### Explanation:

This quadratic equation isn't able to be factored, so we can solve by using the quadratic formula:

$x = \setminus \frac{- b \setminus \pm \setminus \sqrt{{b}^{2} - 4 a c}}{2 a}$

In this case:

$a = 3$

$b = 6$

$c = - 185$

Plugging in yields:

$x = \setminus \frac{- 6 \setminus \pm \setminus \sqrt{{6}^{2} - 4 \left(3\right) \left(- 185\right)}}{2 \left(3\right)}$

$x = \setminus \frac{- 6 \setminus \pm \setminus \sqrt{36 + 2220}}{6}$

$x = \setminus \frac{- 6 \setminus \pm \setminus \sqrt{2256}}{6}$

$x = \setminus \frac{- 6 \setminus \pm 4 \setminus \sqrt{141}}{6}$

$x = \setminus \frac{6}{- 6} \setminus \pm \setminus \frac{4 \setminus \sqrt{141}}{6}$

$x = - 1 \setminus \pm \setminus \frac{2 \setminus \sqrt{141}}{3}$

$x = 6.9162280580253 , \setminus q \quad x = - 8.9162280580253$