What molar quantity is represented by 3.011xx10^23*"magnesium atoms"?

2 Answers
Dec 29, 2017

If I have a half a dozen magnesium atoms, how many atoms would that be?

Explanation:

And this question is PRECISELY the same as the one you asked EXCEPT that we use "the dozen" as our metric instead of the "Avocado number", i.e. N_A=6.022xx10^23*mol^-1

And so we take the product...

6.022xx10^23*mol^-1xx0.5*mol-=3.011xx10^23*"magnesium atoms". You know the mass of this quantity....

Dec 29, 2017

3.01 xx10^23 "atoms".

Explanation:

6.02xx10^23 (Avogadro's constant) indicates the number of atoms in a mole of any element, so basically:

"1 mole of Mg " -> " " 6.02 xx10^23 "atoms"
"0.5 moles of Mg " -> " " "? atoms"

So

"0.5 moles" xx ( 6.02xx10^23 "atoms")/"1 mole"

which equals to half of Avogadro's constant.