Question #7cc35

1 Answer
Douglas K.
Jan 11, 2018

#"side"_"plate" = 4/3sqrt15+ 6" cm"#

Explanation:

The volume of the box is:

#"side"_"box"^2 xx "height" = 80" cm"^3#

Assuming the sides of the box are folded up to make the the height of the box same as one the side of the squares, then the #"height = "3" cm"# and the box has a square bottom.

The area of the square bottom of the box is:

#"side"_"box"^2=(80" cm"^3)/(3" cm")#

#"side"_"box" = sqrt(80/3)" cm"#

#"side"_"box" = 4/3sqrt15" cm"#

Add #6" cm"# to the side of the box to obtain the side of the original square plate:

#"side"_"plate" = 4/3sqrt15+ 6" cm"#

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