Question #3a12c

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Answer 1 · 2017-12-21T19:29:32

#y=4sin(2/3x)#

If we write a trigonometric equation in the form:

#y=asin(bx+c)+d#

Then:

Amplitude is a

Period is #(2pi)/b# ( normal period of function divided by b )

Phase shift is #(-c)/b#

Vertical shift is d

So we need:

#a= 4#

#(2pi)/b=3pi=>b=2/3#

So equation will be:

#y=4sin(2/3x)#