Question #26d88

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Answer 1 · 2017-10-16T11:16:18

#z=+-1.76#

we want #z# such that

# P( -Z < z < Z )=0.92#

with the distribution

# X~N(0,1)#

now the Normal distribution for #Z #

is symmetrical about the mean #0#

so

# P( -Z < z < Z )=2[P( Z< z)-P (Z< 0)]#

this leads us to:

#P( Z < z)= 0.46+0.5=0.96#

from tables

#P( Z < z)= 0.46+0.5=0.96=>z=1.75#

#z=+-1.76#