Question

Question #ecf38

Answer 1

`c=200" J"//("kg"*"K"))`

Explanation:

We begin with the equation

`color(blue)(Q=mcDeltaT)`

Where:

• `Q` is the energy input into the substance by heating
• `m` is the mass of the substance
• `DeltaT` is the change int temperature experienced by the substance

We are given values for `Q, m` and `DeltaT`. We can rearrange the equation to solve for `c` using a little algebra.

`=>c=Q/(mDeltaT)`

Given:

• `Q=400"J"`
• `m=0.1"kg"`
• `DeltaT=20^o"C"=20"K"`

(Note that `DeltaT` for the Celsius scale is equivalent to `DeltaT` for the kelvin scale)

`=>c=(400"J")/((0.1"kg")(20"K")`

`=>=color(blue)(200" J"//("kg"*"K"))`