# Question #f71f9

##### 1 Answer

#### Answer:

p= 0.6001

q= 0.399

pq= 313.177 --> 313

#### Explanation:

We know that our Population X is 653 individuals. Of this population 104 have floppy ears (Xf). We know that p (short) is dominant over q (floppy).

Basic equations for Hardy Weinberg:

p + q = 1

Taking the square root of this number gives us the frequency

q= 0.399

Now we can enter this into p+q=1

This means that p= 1 - q which solves to 0.6001

Now that we now both p and q we can start calculating the frequencies of the genotypes

2pq gives 2 * 0.6001 * 0.399 = 313.177 which gets rounded up to 313

To find the frequency of each genotype we divide the total population by each genotypes' population.

fpp =

fpq =

fqq=