Question

Does the `pH` get higher as the acid concentration increases?

Answer 1

Well no.......

Explanation:

In aqueous solution an acid `HA` undergoes the following equilibrium....

`HA(aq) + H_2O(l) rightleftharpoonsH_3O^+ + A^-`

Clearly, `K_a=([H_3O^+][A^-])/([HA(aq)])`

And for the reverse reaction...

`A^(-) + H_2O(l) rightleftharpoonsHA(aq) + HO^-`

Clearly, `K_b=([HA(aq)][HO^-])/([A^-])`

And #K_axxK_b=([H_3O^+][A^-])/([HA(aq)]) *([HA(aq)][HO^-])/([A^-])#

`=[H_3O^+][HO^-]=K_w=10^-14`

And should we take `-log_10` of BOTH sides, we gets....

`-log_10[H_3O^+]-log_10[HO^-]=-log_10(10^-14)=14`

`underbrace(-log_10[H_3O^+])_(pH)underbrace(-log_10[HO^-])_(pOH)=14`

And so `pOH + pH=14`

And likewise we could take...`-log_10` of `K_axxK_b` to get....

`pK_a+pK_b=14`