If the vectors #2hat(i)-3hat(j)+5hat(k)# and #3hat(i)+ahat(j)-2hat(k)# are perpendicular, then what is the value of #a# ?

1 Answer
Oct 18, 2017

#a = -4/3#

Explanation:

#2hat(i)-3hat(j)+5hat(k)# and #3hat(i)+ahat(j)-2hat(k)# are perpendicular if and only if their dot product is #0#.

#(2hat(i)-3hat(j)+5hat(k)).(3hat(i)+ahat(j)-2hat(k)) = 6-3a-10#

#color(white)((2hat(i)-3hat(j)+5hat(k)).(3hat(i)+ahat(j)-2hat(k))) = -3a-4#

So we require:

#0 = -3a-4#

Hence:

#a = -4/3#