Question #c7175

1 Answer
Oct 20, 2017

#x = 0.8 , x= -0.8#

Explanation:

What this is really stating is, that if we raise #e# to the power of #0# it will equal #x^2+0.36# .So:

#e^0= x^2+0.36#

#e^0 = 1#

#1=x^2+0.36#

#x^2= 1- 0.36= 0.64=> x= +-sqrt(.64)# #color(white)(8)x = 0.8, x= -0.8#