Well, you need another reactant to write a reaction...
#"PbO"_2(s) + 4"HCl"(aq) -> "PbCl"_4(aq) + 2"H"_2"O"(l)#
#"PbCl"_4(aq) -> "PbCl"_2(s) + "Cl"_2(g)#
You cannot write a reaction with just lead(IV) oxide in water. It is very insoluble unless you add strong acid.
On the other hand, if you wish to write a chemical FORMULA, then you must know that oxygen atom typically assumes a
Oxygen is more electronegative than lead by far, and thus it assumes a negative oxidation state because it wants the electrons more to a first approximation.
It CANNOT be assumed that lead it is a
That automatically means a
#color(blue)("PbO"_2)#is lead(IV) oxide.
The reaction to form Lead Oxide
Lead Pb has a common oxidation number of +4
Oxygen O has a common oxidation number of -2
It takes 2 Oxygen atoms to balance one Lead atom
so the formula for Lead Oxide is
The equation for forming Lead Oxide is
I hope this is what your meant by your question.
I think you might have meant to ask how to write lead (IV) oxide as a chemical formula .
The chemical formula for lead (IV) oxide is:
Formulas describe one compound.
The Roman numeral IV indicates the oxidation state of the lead ion in this compound.
Lead (IV) means the
Oxide ion is always
To balance the charges you need two
Here are some other examples of compounds that use Roman numerals to tell you about the oxidation state of metals.
Hope this helps!