Question

Question #92aa1

Answer 1

vertex = (h,k) = (1,3)

focus = (h, (k+p)) = (1, 6)

directrix is y = k-p, y = 3 - 3 = 0

Explanation:

The standard form is
`(x-h)^2 = 4p(y-k)`
where focus is ( h, (k+p)),
directrix is y = k -p
vertex is (h,k)

`y - 3 = (1/12)(x-1)^(1/2)`
`12(y-3) = (x-1)^2`
`(x-1)^2 = 4*3(y-3)`
Where h = 1, k = 3, p = 3

vertex = (h,k) = (1,3)

focus = (h, (k+p)) = (1, 6)

directrix is y = k-p, y = 3 - 3 = 0
graph{(1/12)(x-1)^2+3 [-10, 10, -5, 5]}