What ions exists in #Be_2C#, and would this react with water?

1 Answer
Oct 23, 2017

Beryllium hydroxide and methane....?

Explanation:

You have formally a #C^(4-)# and #2xxBe^(2+)# ions as written (and I don't really believe it)....and so,,,,

#Be_2C(s) + 4H_2O(l) rarr 2Be(OH)_2(s)+CH_4(g)uarr#

Note that calcium carbide undergoes a similar (and actual) reaction...

#Ca^(2+)""^(-):C-=C:^(-)(s) + 2H_2O(l) rarr HC-=CH(g)uarr +2Ca(OH)_2(aq)#