Question

Question #6e264

Answer 1

`e^(-ln x)=color(red)(1/x)`

Explanation:

Remember
[1]`color(white)("XXX")a^(-b)=1/(a^b)`
and
[2]`color(white)("XXX")e^(ln x)=x`

Therefore
`e^(-ln x) = 1/(e^(ln x))=1/x`