# Question #424e2

Oct 25, 2017

I am assuming that you want to find TWO numbers that give you $16$ when you add and $2$ when you subtract the second from the first number.

The first number is $9$. The second number is $7$.

#### Explanation:

If your question is different, let me know.

Let the two numbers be $A$ and $B$.

We are given that

$A + B = 16 \text{ }$(Equation 1)

$A - B = 2 \text{ }$ (Equation 2)

Using Equation 1, we can find the value of $A$ as follows:

$A = \left(16 - B\right)$

Substitute this value of $A$ in Equation 2. We get

$\left(16 - B\right) - B = 2$

That is,

$16 - B - B = 2$

$16 - 2 B = 2$

$- 2 B = 2 - 16$

$- 2 B = - 14$

$2 B = 14$

$B = \left(\frac{14}{2}\right) = 7$

Substitute this value of $B$ in Equation 1, to find the value of $A$

$A + 7 = 16$

$A = 16 - 7$

$A = 9$

Hence,

$A = 9 \mathmr{and} B = 7$