Question #1100b

Oct 25, 2017

No, $\frac{2}{\sqrt{8}}$ is an irrational number.

Explanation:

$\frac{2}{\sqrt{8}}$ is an irrational number. The definition of a rational number is a number that is an integer divided by an integer in the form of $\frac{p}{q}$ (i.e. $1 , \frac{1}{2}$).

$\frac{2}{\sqrt{8}}$ is in the form of $\frac{p}{q}$ but $\sqrt{8}$ is not an integer, it is a rational number.

So then what is an irrational number? An irrational number is basically when the number gives you an ongoing decimal.
$\frac{2}{\sqrt{8}} = 2.8284 \ldots .$