Question

Question #58cde

Answer 1

Not a solution.

Explanation:

`f(x) = 4sin^2 (x/2 + pi/3) - 3`
Replace x by `pi/3` into the expression.
`sin (x/2 + pi/3) = sin (pi/6 + pi/3) = sin ((3pi)/6) = sin pi/2 = 1`
`4sin^2 (x/2 + pi/3) = 4(1) = 4`
`f(x) = 4 - 3 = 1`
Since `f(x) != 0`, therefor, `pi/3` isn't a solution of f(x)