Question #a4e55

1 Answer
Cesareo R.
Oct 25, 2017

See below.

Explanation:

According to

#{(x = r costheta),(y = r sintheta):}# we have

#r^2=4a^2r^4cos^2theta sin^2theta# or

#r=pm2ar^2costheta sin theta# or

#r = pm1/(2acostheta sintheta) = pm 2/(2a sin(2theta)) = pm 1/(a sin(2theta))#

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