How do you expand #log_7(216)#?
1 Answer
Oct 25, 2017
The answer is:
#3log_(7) 3 + 3log_7 2#
Explanation:
We can rewrite this as
#log_7(3^3 * 2^3)#
It follows that this is equivalent to
#log_7 3^3 + log_7 2^3#
#3log_7 3 + 3log_7 2#
Hopefully this helps!