Question #c76dd

1 Answer
Oct 26, 2017

#= b^5 - 10 b^4 + 40 b^3 - 80b^2 + 80b - 32#

Explanation:

#(b-2)^5 = b^5 + _5C_1*b^4*(-2) + _5C_2 b^3 *( -2)^2 + _5C_3 b^2 (-2)^3 + _5C_4 b * (-2)^4 + (-2)^5#

#= b^5 - 10 b^4 + 40 b^3 - 80b^2 + 80b - 32#

Note #: _5C_1 =_5C_4 = 5,#

#:_5C_2 = _5C_3= (5*4)/(1*2) = 20/2 = 10#

#:_5C_5 = 1#