Question

Position-time equation for a train is `x_t=2.9m+(8.5m/s)t+(2.9m/s^2)t^2`. What is the position at `4.9s` up to three significant digits?

Answer 1

`114` `meters`

Explanation:

As position-time equation for the train is `x_t=2.9m+(8.5m/s)t+(2.9m/s^2)t^2`

Position at time `4.9s` is `x_t=2.9m+(8.5m/s)4.9s+(2.9m/s^2)4.9^2s^2`

= `2.9m+(8.5xx4.9)m+(2.9xx4.9^2)m`

= `2.9m+41.65m+69.629m`

= `114.179m`

~= `114m` up to three significant digits.