Question #8775f

1 Answer
Saliha
Oct 27, 2017

#8 ATPs#

Explanation:

#ATP# produced during oxidative phase of glycolysis #=# #4#

#ATP# used during preparatory phase of glycolysis #=# #2#

#NADH# produced during oxidative phase of glycolysis #= 2#

As
#1NADH# #=# #3ATP#
So,
#2NADH = 6ATP#
Thus;
Total #ATP# produced #= 6 + 4 = 10#

#Net ATP# produced after glycolysis # = 10 - 2 = 8 ATPs#

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