Question #a0799

1 Answer
sankarankalyanam
Jan 15, 2018

#/_(BCD) = color(blue)(80^0)#

Explanation:

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In rhombus ABCD,

#/_(ABD) = 50^0 #

BD is the angular bisector of #/_(ABC)#

#:. /_(ABD) = /_(CBD) = 50^0# I.e. #/_(ABC) = 50 + 50 = 100^0#

#/_(ABC) + /_(BCD) = 180^0# since AB and CD are parallel and BC is a transversal.

#:./_(BCD) = 180 - (100) = 80^0#

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