Question #98f95

1 Answer
Oct 30, 2017

Answer:

The concentration of the salicylic acid solution is #"0.00586 mol/L"#, abbreviated #"000586 M"#.

Explanation:

#"molarity"=("mol solute")/("liters of solution")#

The unit of molarity is #"mol/L"#, abbreviated #"M"#. You first need to determine the moles of salicylic acid #("C"_7"H"_6"O"_3")# in #"0.810 g"#.

Divide the given mass by the molar mass of salicylic acid #("138.122 g/mol")#. You can calculate the molar mass or look it up. Since molar mass is a fraction, #"g"/"mol"#, you can divide by multiplying the given mass by the inverse of the molar mass, #"mol"/"g"#.

#0.810color(red)cancel(color(black)("g C"_7"H"_6"O"_3))xx(1"mol C"_7"H"_6"O"_3)/(138.122color(red)cancel(color(black)("g C"_7"H"_6"O"_3)))="0.00586 mol C"_7"H"_6"O"_3"#

#"molarity"=(0.810"mol C"_7"H"_6"O"_3)/(1.00"L")="0.00586 mole/L"#