# Question 98f95

##### 1 Answer
Oct 30, 2017

The concentration of the salicylic acid solution is $\text{0.00586 mol/L}$, abbreviated $\text{000586 M}$.

#### Explanation:

"molarity"=("mol solute")/("liters of solution")

The unit of molarity is $\text{mol/L}$, abbreviated $\text{M}$. You first need to determine the moles of salicylic acid $\left(\text{C"_7"H"_6"O"_3}\right)$ in $\text{0.810 g}$.

Divide the given mass by the molar mass of salicylic acid $\left(\text{138.122 g/mol}\right)$. You can calculate the molar mass or look it up. Since molar mass is a fraction, $\text{g"/"mol}$, you can divide by multiplying the given mass by the inverse of the molar mass, $\text{mol"/"g}$.

0.810color(red)cancel(color(black)("g C"_7"H"_6"O"_3))xx(1"mol C"_7"H"_6"O"_3)/(138.122color(red)cancel(color(black)("g C"_7"H"_6"O"_3)))="0.00586 mol C"_7"H"_6"O"_3"#

$\text{molarity"=(0.810"mol C"_7"H"_6"O"_3)/(1.00"L")="0.00586 mole/L}$