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Answer 1 · 2017-10-31T18:54:13

#P0.092(3dp)#

#X=" the number of heads"#

the probability of a head #=0.5#

we have a Binomial distribution

in general

#color(red)(X~B(n,p))--(1)#

#color(red)(P(X=r)=((n),(r))p^r(1-p)^(n-r))--(2)#

in this case

#X~B(15,0.5)#

we want

#P(X=10)#

using #(2)#

#P(X=10)=((15),(10))0.5^(10)0.5^(5)#

#P(X=10)=0.092(3dp)#