Question #ed706

1 Answer
Oct 31, 2017

see below

Explanation:

we need the transformation eqns

#r^2=x^2+y^2#

#x=rcostheta#

#y=rsintheta#

#r=sqrt(rcostheta+2)#

#=>r^2=rcostheta+2#

using the above transformations

#x^2+y^2=x+2#

#x^2-x+y^2=2#

complete the square

#(x-1/2)^2+y^2-1/4=2#

#(x-1/2)^2+y^2=9/4#

a circle with centre #(1/2,0)#

radius# =sqrt(9/4)=3/2#