Question #ae7f0

1 Answer
F. Javier B.
Feb 15, 2018

#r(-theta)=3+2sin(-theta)#

Explanation:

A function is even if #f(-x)=f(x)# and then is simmetric regarding #y# axis
A function is odd if #f(-x)=-f(x)# and then simmetric regarding the origin of coordinates #O(0,0)#

Thus the test for simetry for our function is

#r(-theta)=3+2sin(-theta)#

We know that for every #theta in [0,2pi]#, #sin (-theta)=-sin (theta)#. Thus we have

#r(-theta)=3+2sin(-theta)=3-2sin(theta)!=-r(theta)# and #!=r(theta)#. Thus our function is neither odd nor even and has no simmetry

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