How many water molecules in a #3.64*g# mass of water?

1 Answer
anor277
Nov 1, 2017

Approx. #1.22xx10^23# water molecules....

Explanation:

We (i) assess the molar quantity...

#(3.64*g)/(18.01*g*mol^-1)=0.202*mol#

But by specification, #1*mol# specifies #"Avogadro's number"#, #6.022xx10^23*mol^-1# of individual particles....

And so (ii) we take the product....

#6.022xx10^23*mol^-1xx0.202=1.22xx10^23# #"water molecules"#. Why does this represent #3.65xx10^23*"individual atoms"#, and what is the mass of this molar quantity?

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