Question

A bag contains 36 numbered tiles. In how many ways can 3 tiles be drawn if A. there is no replacement, and B. there is replacement?

Answer 1

`A=42,840. B=46,656`

Explanation:

A

The first number can be any one of 36 numbers.
The second number can be any one of 35 remaining choices.
The third number can be any one of 34 remaining choices.

And so we have:

`36xx35xx34=42,840`

B

The first, second, and third numbers can be any one of 36 numbers, and so:

`36xx36xx36=36^3=46,656`